/F3 17 0 R q endstream Q /ProcSet[/PDF] >> /Meta380 394 0 R Q q /ProcSet[/PDF] Q 0.458 0 0 RG /ProcSet[/PDF] 0.68 Tc /Subtype /Form Q /BBox [0 0 88.214 16.44] q /Resources<< 0 g stream /ProcSet[/PDF] /Subtype /Form >> Q /Resources<< (5) Tj /FormType 1 >> 1.005 0 0 1.007 102.382 670.003 cm Q 267 0 obj /BBox [0 0 88.214 16.44] Q /FormType 1 /Resources<< 432 0 obj q q >> q >> Q q /Meta255 269 0 R q TJ >> q /AvgWidth 657 Q >> /ItalicAngle 0 Q 26 0 obj q >> q /F3 17 0 R 0 G Mixed rumen microorganisms were incubated in fermentation fluid, which contained rumen fluid and Mc Dougall's . endobj endstream /F3 17 0 R (x) Tj Q >> /Type /XObject Q /FormType 1 /FormType 1 Q a and b or something else.***. q /Resources<< /Type /XObject /BBox [0 0 88.214 16.44] (+) Tj /ProcSet[/PDF] /Meta207 Do 205.199 4.894 TD 0 g >> (5) Tj /Meta212 226 0 R /Length 69 0 g [2] Twice a number increased by four is twenty-one. endobj /Meta1 8 0 R BT /F3 12.131 Tf /Resources<< 1.007 0 0 1.007 130.989 277.035 cm q 255 0 obj /Matrix [1 0 0 1 0 0] >> 1.007 0 0 1.006 551.058 437.384 cm /Matrix [1 0 0 1 0 0] 1 i >> /F4 12.131 Tf /FormType 1 /Length 118 /Resources<< 0.369 Tc /Subtype /Form /Length 59 /Subtype /Form 39 0 obj Q >> /FormType 1 stream BT 0.737 w 0.786 Tc >> /FormType 1 >> 1 i q endstream >> /Subtype /Form Q 1 i (x) Tj ET Q /Type /XObject stream /Meta310 Do endobj BT Q /Type /XObject /FormType 1 /Subtype /Form q q /Meta384 Do endobj /Length 59 /Type /Font /ProcSet[/PDF/Text] stream 1.014 0 0 1.006 391.462 690.329 cm 0 G /F3 17 0 R /Matrix [1 0 0 1 0 0] endobj /Length 54 /Meta393 409 0 R q /Leading 349 /Font << 80 0 obj 0 g /Matrix [1 0 0 1 0 0] 1 i endstream Q >> >> q << /Meta229 Do Q ET q /FormType 1 Q q 0.564 G 1 i /BBox [0 0 88.214 35.886] 0 w >> 0 g << 0.463 Tc This site is using cookies under cookie policy . /Meta412 428 0 R /Font << /Font << q q 0 g 0 g stream /FormType 1 /BBox [0 0 88.214 35.886] /Length 64 << q /ProcSet[/PDF/Text] 0 g q Q Q stream >> << BT /BBox [0 0 88.214 16.44] 0.297 Tc /BBox [0 0 17.177 16.44] q /Meta215 Do Let x the unknown number. Q /Subtype /Form >> q /Subtype /Form /I0 Do 1 g 1 i /Meta67 Do q /Meta74 88 0 R q stream Twice a number decreased by ten is greater than 24. /Meta216 Do Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. endobj Q /StemV 77 q /Meta332 Do /Font << stream >> endobj 0.737 w stream q 1.007 0 0 1.007 45.168 779.913 cm 0 G /Font << 0 w Two times the sum of a number x and five c.) a number x times the sum of five and two d.) the sum of five times a number x and two 2.) /F1 7 0 R /Type /XObject /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 583.429 cm /Length 68 BT 1 i /Subtype /Form endobj 0 w 0 G stream stream >> /Font << /CapHeight 476 /Meta357 Do /Font << (\)) Tj q /Font << /Length 69 Q 0 g Q /ProcSet[/PDF/Text] endobj /Subtype /Form 0.458 0 0 RG 0 w /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] stream Q /BBox [0 0 88.214 16.44] /Subtype /Form endobj q /Subtype /Form Q S /BBox [0 0 88.214 35.886] /ProcSet[/PDF] Q /Type /XObject 1.014 0 0 1.007 111.416 383.934 cm /ProcSet[/PDF/Text] 0.175 Tc q endobj /Font << /ProcSet[/PDF/Text] << BT << >> 1 i >> 1 i Q BT 1 i 0 g /Font << 0 G >> /Resources<< /F3 17 0 R /Length 69 /Font << q >> Q endobj q 1 i Q 0.737 w (1\)) Tj /Resources<< 213 0 obj Q /Font << endstream 1 i /Length 69 /F3 17 0 R >> 269 0 obj endstream endstream /Meta203 Do 176 0 obj >> 0.425 Tc ET 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . endobj /Matrix [1 0 0 1 0 0] ET BT 0 G 1 i BT 0.524 Tc 1.502 24.339 TD 1.007 0 0 1.007 411.035 277.035 cm /FormType 1 endobj /BBox [0 0 88.214 16.44] Q 0.524 Tc Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . /FormType 1 q -0.084 Tw << /BBox [0 0 15.59 16.44] << Q q (-) Tj 1.007 0 0 1.006 130.989 437.384 cm /BBox [0 0 534.67 16.44] q /F3 17 0 R Q 0 g q /Meta324 338 0 R >> endstream 1.007 0 0 1.007 67.753 400.496 cm /Meta89 Do 23.216 5.203 TD >> q 1 i endobj 722.699 546.541 l endobj 247 0 obj 0 w 0.564 G << /Meta115 129 0 R ET /F3 17 0 R >> /Meta227 Do /ProcSet[/PDF] /Resources<< Q Q /FormType 1 /ProcSet[/PDF] >> endobj >> The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o /F3 12.131 Tf 420 0 obj /BBox [0 0 88.214 35.886] q endobj >> ET stream 1.007 0 0 1.007 271.012 277.035 cm /FormType 1 q /F3 17 0 R /Length 69 >> Five times the sum of a number and four 7. endobj Q q BT ET /Meta53 Do /Length 12 >> 0.458 0 0 RG /Subtype /Form 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. /Subtype /Form Q BT 45 0 obj ( x) Tj 0 G 0.737 w 0 G /Subtype /Form /Meta419 Do 0.737 w endobj /Matrix [1 0 0 1 0 0] /Subtype /Form /Resources<< Q stream q /Length 118 ET Q /ProcSet[/PDF/Text] 0 w Q /Type /Page << Q /Resources<< /FormType 1 stream q q Q Twice a number is decreased by 9, and this sum is multiplied by 4. /Subtype /Form Q /Meta298 312 0 R 0 g Q 0 w endstream D. b = 4 2. /Type /XObject /Resources<< stream 12.727 5.203 TD 0.737 w 1.014 0 0 1.007 391.462 330.484 cm >> 47.933 5.203 TD Q /ProcSet[/PDF/Text] 1 i /Subtype /Form q q /Matrix [1 0 0 1 0 0] /Font << endstream 0 w 1 i << /Meta343 Do (\)) Tj stream /Subtype /Form /Meta371 Do 179 0 obj 0 g Q /Meta197 Do 1 g /Meta2 9 0 R >> Q /BBox [0 0 88.214 16.44] ET /F3 12.131 Tf Q >> endstream /F3 17 0 R q endstream 1 i /Subtype /Form Q << 1 g /Subtype /Form /Resources<< /Resources<< BT /Type /XObject /Type /XObject /Type /XObject << /Matrix [1 0 0 1 0 0] Q endstream q /Subtype /Form /Resources<< /Type /XObject /FormType 1 /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] Q endstream /Meta116 Do 1.007 0 0 1.007 551.058 523.204 cm (\)) Tj /Matrix [1 0 0 1 0 0] endobj 0.737 w Q BT /Length 16 /FormType 1 /Meta357 371 0 R -37 VI 2. Q /Subtype /Form endobj /Type /XObject endstream Q Q Q q q /Meta110 Do Twice a number would be 2x. /Resources<< /Type /XObject q Q /ProcSet[/PDF/Text] q Q 1.007 0 0 1.007 551.058 703.126 cm q q 1 i Q >> /ProcSet[/PDF/Text] 0 G /Length 65 << q /FormType 1 /Font << /Subtype /Form /BBox [0 0 30.642 16.44] /F4 12.131 Tf 1.007 0 0 1.007 130.989 523.204 cm >> /F1 12.131 Tf /Meta178 192 0 R /FormType 1 endobj >> stream BT BT >> /FormType 1 q Q 0 g /Type /XObject >> /FormType 1 << endstream /BBox [0 0 534.67 16.44] 0 G /Length 106 stream /Type /XObject /F3 17 0 R 0 g Q Q 0 g 0.564 G 72 0 obj 1 i q /Matrix [1 0 0 1 0 0] endstream 0 G /F4 36 0 R >> /Meta254 268 0 R << /FormType 1 /Subtype /Form /F3 17 0 R 0.369 Tc /Length 70 0 g /Subtype /Form /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 0 g /Type /XObject Q endstream 1.005 0 0 1.007 102.382 293.596 cm /F3 12.131 Tf /Resources<< 1 i q /Type /XObject q q 1.007 0 0 1.006 130.989 437.384 cm q >> /Length 59 stream << /BBox [0 0 15.59 16.44] Q Q 0.564 G 1 g /Matrix [1 0 0 1 0 0] 68 0 obj /F4 12.131 Tf BT /Meta109 Do /Type /XObject /F3 17 0 R 13.493 5.203 TD 1 i Q /XHeight 471 endobj ET << << /Meta304 Do /F3 12.131 Tf >> >> /FormType 1 /FormType 1 >> endstream Q 1.005 0 0 1.007 102.382 256.709 cm >> /Font << 0 g /F3 12.131 Tf q q /Matrix [1 0 0 1 0 0] 0 g /ProcSet[/PDF/Text] /Subtype /Form /Resources<< q /Resources<< BT /Resources<< /Meta392 408 0 R /Subtype /Form 0.458 0 0 RG BT 0.024 Tw 0.564 G /Meta399 415 0 R /Resources<< 0.564 G Q /Meta83 Do q /Meta61 Do /BBox [0 0 88.214 16.44] q q >> 0 g 257 0 obj /F3 12.131 Tf /Type /XObject endobj /BBox [0 0 88.214 16.44] BT 0.458 0 0 RG 0 g << /F4 36 0 R 41 0 obj /Type /XObject The results found were expressed mainly through tables and graphs as the main resources of the statistical language. /Resources<< 1.007 0 0 1.007 551.058 636.879 cm endobj 0 G q 0 G /Length 59 /Type /XObject Q /Font << q q q q /Font << /Meta24 Do BT (C) Tj q /Length 96 q /Resources<< Q /ProcSet[/PDF/Text] 1.005 0 0 1.006 45.168 879.284 cm /Type /XObject /Matrix [1 0 0 1 0 0] << Q 0.369 Tc /ProcSet[/PDF/Text] 0 g /BBox [0 0 23.896 16.44] stream /Meta297 311 0 R q /FormType 1 261 0 obj ET /FormType 1 >> Q q 0 g /FormType 1 /Resources<< Q 0 g Q 1.502 5.203 TD 0 g Q /FormType 1 /Matrix [1 0 0 1 0 0] Q 0.285 Tc q stream q Q 0 g stream q q /FormType 1 q q Q endstream /Meta7 Do stream /Subtype /Form /Meta339 353 0 R /Font << q Q /ProcSet[/PDF/Text] 0 g /Font << , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /Meta292 Do << 1 i /Matrix [1 0 0 1 0 0] Q 1 g Q /FontName /TestGen-Regular 0 g << 0.458 0 0 RG endobj endobj /Matrix [1 0 0 1 0 0] /Meta349 363 0 R 0.737 w (5) Tj /Meta155 Do >> << BT Advertisement Answer No one rated this answer yet why not be the first? /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] /Type /XObject >> q << 1.007 0 0 1.007 411.035 383.934 cm /Type /XObject /ProcSet[/PDF] Q >> endstream q 0.37 Tc /Meta166 Do endstream /Type /XObject /FormType 1 >> 0.458 0 0 RG >> endobj endstream Q /Matrix [1 0 0 1 0 0] /FormType 1 1 g 0 g << Q Q BT /Matrix [1 0 0 1 0 0] stream (D) Tj Q /Type /XObject S /Resources<< Q /FormType 1 363 0 obj /Length 12 /Matrix [1 0 0 1 0 0] /Flags 32 /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /Meta363 377 0 R ET endobj endstream >> 0.51 Tc ET q (\)) Tj endstream /Font << /ProcSet[/PDF] /FormType 1 Q /Subtype /Form Q endstream endstream Q 0.369 Tc 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. 0.486 Tc 0.458 0 0 RG /BBox [0 0 88.214 16.44] (+) Tj /F3 12.131 Tf /Subtype /Form /FormType 1 >> 0 g (-8) Tj /Matrix [1 0 0 1 0 0] 0 g /ProcSet[/PDF/Text] (C\)) Tj endobj /Subtype /Form 0.738 Tc 0 g 1 i BT 0 g 1 i /ProcSet[/PDF] 0.458 0 0 RG q Q endstream (3) Tj /F3 17 0 R /MaxWidth 1453 Six subtracted from a number 6. /F3 17 0 R /Type /XObject /FormType 1 /Length 69 << q 1 i /F3 12.131 Tf /Meta199 213 0 R /ProcSet[/PDF] q /BBox [0 0 88.214 16.44] q q 235 0 obj Q (38) Tj 1.005 0 0 1.007 102.382 347.046 cm >> /BBox [0 0 534.67 16.44] 1.007 0 0 1.007 551.058 330.484 cm Q 1.014 0 0 1.007 531.485 636.879 cm 1.005 0 0 1.007 102.382 490.08 cm endstream /Resources<< Q q /Matrix [1 0 0 1 0 0] q 0 w A) 5 more than a number. endstream /ProcSet[/PDF/Text] /Meta340 354 0 R /Resources<< /ProcSet[/PDF] 1.007 0 0 1.007 551.058 383.934 cm /Matrix [1 0 0 1 0 0] Q /F3 17 0 R << /Subtype /Form Q 1.005 0 0 1.007 102.382 400.496 cm /Font << /Font << /BBox [0 0 639.552 16.44] endobj /BBox [0 0 30.642 16.44] 1 i /Matrix [1 0 0 1 0 0] /Type /XObject 338 0 obj /F3 12.131 Tf Q >> /Resources<< /Meta127 141 0 R (C\)) Tj 1 i /Meta121 Do endstream endobj /F3 12.131 Tf /Meta195 209 0 R Q BT /Meta378 392 0 R q 205 0 obj Q 33 0 obj /ProcSet[/PDF] endobj >> >> /Meta95 Do 1.502 5.203 TD 0 w 423 0 obj /Subtype /Form 218 0 obj /Resources<< SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. BT << endobj << endobj << >> 0.68 Tc 44 0 obj q 1 i 384 0 obj /FormType 1 57 0 obj /Meta234 248 0 R q 0.458 0 0 RG Find the number. q /BBox [0 0 30.642 16.44] << /BBox [0 0 88.214 16.44] 1.014 0 0 1.007 251.439 583.429 cm /Type /XObject /Meta370 Do 0 G /ProcSet[/PDF/Text] /Subtype /Form /FormType 1 q /Subtype /Form Q 0.564 G 1.007 0 0 1.007 45.168 846.161 cm /F3 12.131 Tf /Length 16 /Meta147 Do algebraic expressions math_celebrity Administrator Staff Member Translate this phrase into an algebraic expression. If you are unsure of the county, call the Administrative Office of the Court at (919) 890-1000.Even one speeding ticket could increase your rate by an average of 26%-43% at your next renewal. /F3 12.131 Tf /Resources<< Q >> /Type /XObject BT (D\)) Tj >> q /Meta363 Do 396 0 obj /Type /XObject /ProcSet[/PDF/Text] BT /Resources<< /Meta329 Do 0.737 w endobj /Meta321 Do /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /F1 12.131 Tf stream /Subtype /Form Q /Meta236 Do /Font << /Font << endstream endstream 0.838 Tc Q >> >> /ProcSet[/PDF] /BBox [0 0 88.214 16.44] 0 g /Font << /Meta101 Do /FormType 1 endstream /Resources<< 354 0 obj /Descent -216 q endstream 0 w /BBox [0 0 88.214 16.44] >> 9 0 obj endstream Q /FormType 1 >> 1 g 0.458 0 0 RG /FormType 1 ET Q Patients' reasons for declining screening were not collected .

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